Finish the last question according to the lab data

Name Jing Huang Date Peis Pd Lab- EMF and Internal resistance of a battery Equipment: 2 multimeters. One setup as an ammeter, the other as a voltmeter potentiometer (aka, variable resistor) lightbulb in holder 4 D size batteries in holders alligator wires Setup the circuit as shown. The potentiometer is connected using the middle connector and either of the side connectors. Set up the circuit and the potentiometer so that the light bulb is glowing. The potentiometer will then be at zero resistance. One can turn the knob on the potentiometer to increase its resistance. As a result the current in the circuit will decrease. Because of the batteries' internal resistance, the batteries' terminal voltage will also change. Vary the potentiometer resistance to collect terminal voltage and current data for every 0.1 Volts. Terminal Voltage 5. 82 5- 92 6.02 6.12 6.22 6-32 6.42 6-52 Current 0.37 10.34 0. 33/ 0.31 0. 29 0.28 0. 26 0.25 Write the equation governing terminal voltage and EMF. No Numbers. V= - VL +E. Create an appropriate plot with a line of best fit. (next page). In the space below, write the equation of best fit, and obtain the internal resistance and the EMF of a single battery. (Depending on your data, you may wish to have a break in your graph axis values) y = - 5. 88 x+7.96 Internal resistance = 5:88 EMF = 7-96 What is the maximum current that a D battery can deliver? 0 = - 5.88 x +7.96 * = 1.35 The maximum current that a D battery can deliever is about 1.35 A..y = - 5-88 x +7. 96 2 Terminal voltage 6 ( V ) , 0.05 015 1021 4 0.25 0.35 current ( A ) A typical car battery delivery 12.0V and a maximum of 200. Amps when starting the car. Would it be possible to use D size batteries as a substitute for the car battery? If so, how many batteries would you need and how would they be arranged? Explain. V = - VI+ E. 12 = - 5. 58 ( 200 ) 1