Question: First part of question, second will also be posted. Really not understanding. C webassign.net/web/Student/Assignment-Responses/randomize?pos=1&dep=30022224&tags=autosave#question3250963_1 ES OH 3. [-/16 Points] DETAILS Update : SALGTRIG4 3.4.104. 0/100

First part of question, second will also be posted. Really not understanding.

C webassign.net/web/Student/Assignment-Responses/randomize?pos=1&dep=30022224&tags=autosave#question3250963_1 ES OH 3. [-/16 Points] DETAILS Update : SALGTRIG4 3.4.104. 0/100 Submissions Used MY NOTES ASK YOUR TEACHER A graphing calculator is recommended. A rectangular box with a volume of 2\\/ 3 fts has a square base as shown below. The diagonal of the box (between a pair of opposite corners) is 1 ft longer than each side of the base. X (a) If the base has sides of length x feet, show that x6 - 2x5 - x4 + 12 = 0. Let x be the length, in ft, of each side of the base and let h be the height. The volume of the box is V = 2\\3 = hx2, and so hx2 = 2V3. The length of the diagonal on the base is V x 2 + x 2 = 1 and hence the length of the diagonal between opposite corners of the box is = X + 1. Squaring both sides of the equation and solving for h, we have the following. 2 x 2 + = x2 + 2x + 1 = -x2 + 2x+1 h=

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