1. In the chemical reaction below the enzyme E is a catalyst that converts a raw...

  

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1. In the chemical reaction below the enzyme E is a catalyst that converts a raw material S to product P but itself Does not change. As follows: (1) Reaction S+E •P+E 1.1) (Suppose in order for a product to be produced, n molecules of the raw material must be bonded to the enzyme. Write a function of the food as follows. Parameters e and Vm are equal to what parameters are written in the model and what is the biological meaning have? E+C= e0 = constant) dp dt Vm 1.2) (We want to change model 1.1. To do this, we make two assumptions. First: the chemical process in which the enzyme works on the product itself (autocatalytic process) or S = P. Second: the environmental conditions are such that the product is destroyed at a rate of y Modify the relationship you wrote in Section 1.3 based on these two assumptions. 1.3) Assuming n-1 y=2 k-1=0.5- K2=0.5 - kl=1, the stable and unstable equilibrium points of system 1.2 find. 1.4) Assuming n=2 y-2/3 · k-1=0.5 - k2=0.5 · kl=2 the stable and unstable equilibrium points of system 1.2 find. 1. In the chemical reaction below the enzyme E is a catalyst that converts a raw material S to product P but itself Does not change. As follows: (1) Reaction S+E •P+E 1.1) (Suppose in order for a product to be produced, n molecules of the raw material must be bonded to the enzyme. Write a function of the food as follows. Parameters e and Vm are equal to what parameters are written in the model and what is the biological meaning have? E+C= e0 = constant) dp dt Vm 1.2) (We want to change model 1.1. To do this, we make two assumptions. First: the chemical process in which the enzyme works on the product itself (autocatalytic process) or S = P. Second: the environmental conditions are such that the product is destroyed at a rate of y Modify the relationship you wrote in Section 1.3 based on these two assumptions. 1.3) Assuming n-1 y=2 k-1=0.5- K2=0.5 - kl=1, the stable and unstable equilibrium points of system 1.2 find. 1.4) Assuming n=2 y-2/3 · k-1=0.5 - k2=0.5 · kl=2 the stable and unstable equilibrium points of system 1.2 find.