Question: The incircle of AABC touches BC at D. The difference between BD and CD (R is circumradius) is (A) 4R sin sin ,| BC

The incircle of AABC touches BC at D. The difference between BD

The incircle of AABC touches BC at D. The difference between BD and CD (R is circumradius) is (A) 4R sin sin ",| BC 2. (B) 4R cos 4sin | B-C COS (C) 6 c| b-e (D) 2

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