Question: Flag this Question Question 1 1pts Consider the following example: Prove that for all natural numbers n , 6 n - 1 is a multiple
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Question 1
1pts
Consider the following example: Prove that for all natural numbersn, 6n- 1 is a multiple of 5. When increasingn, what pattern do you notice with 6n- 1?
Group of answer choices
The last digit is always 1.
The last digit is always 6.
It is always a multiple of 6.
It is always a multiple of 5.
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Question 2
1pts
The statement, "6k- 1 is a multiple of 5" can be written as which of the following equations?
Group of answer choices
6k- 1 = 5
6k- 1 = 5jfor some integerj
5(6k- 1) = 1
6k- 1 = 5 +jfor some integerj
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Question 3
1pts
To prove by induction, we start by saying what the statement is that you want to prove: "LetP(n) be the statement... ." Then, to prove thatP(n) is true for all,n 0, what cases must be proven? (Check all that apply.)
Group of answer choices
Base case.
The case whenn= 1.
Inductive case.
The case whennis any arbitrary number.
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Question 4
1pts
Which of the following must be proven as the inductive case in a proof by induction?
Group of answer choices
P(0)
P(k) for allk 0)
P(k+1) for allk 0
P(k) P(k+1) for allk 0
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Question 5
1pts
Consider the following example: "Prove that for all natural numbersn, 6n- 1 is a multiple of 5."In the final step of induction, we want to show that 6k+1- 1 is also a multiple of 5. So, how can we write 6k+1- 1 in terms of 6k- 1?
Group of answer choices
6k+1- 1 = 6 + 6k- 1
6k+1- 1 = 6 * 6k- 1
6k+1- 1 = 6k
6k+1- 1 = 6k+ 1
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