Question: Floor Area: 2 6 0 0 sf ( 1 3 0 0 sf each floor level ) Wall Area: 1 0 5 0 sf (
Floor Area: sf sf each floor level
Wall Area: sf upper level sf lower level
Roof Area: sf
Window Area: sf
Upperlevel wall R Uvalue: Btuhrftdeg F
Lowerlevel wall R Uvalue: Btuhrftdeg F
Roof R Uvalue: Btuhrftdeg F dark color
Windows: wood, single glazed with in clear panes
The foundation wall R is insulated, and the slab is not insulated. The construction tightness of this building is considered loose The family keeps the thermostat at deg F on winter nights, and at deg F on summer days.
The upper floor of the house is airconditioned, and the lower floor naturally maintains
a temperature close to that because it is half underground, with little direct solar gain.
Refer to Table B
a Design temperature for heat loss calculation?
b And Delta Tdeg F
Uvalue of the window? Refer to Table E
Determine the total heat loss Q through the aboveground building envelope.
QBtuhr UBtuhrftdeg F x Aft x Delta Tdeg F
a Q through upperlevel walls?
b Q through lowerlevel walls?
c Q through roofceiling assembly?
d Q through windows?
e Total Q
Determine the total heat loss Q through the belowgrade walls and floor. The
ground temperature is deg F The perimeter of basement wall is ft The depth
of belowgrade floor is ft Refer to Table E
QBtuhr UBtuhrftdeg F x Aft x Delta Tdeg F
a Q through belowgrade walls?
b Q through floor slab?
c Total Q
Determine the heat loss Q from infiltration through cracks in the building
envelope. This is an old residence; thus, no other fresh air source is provided.
The volume of the building is cubic feet. Refer to Table E
Hint: QBtuhrBtuminfthrdeg F x CFM ftmin x Delta Tdeg F
CFMftmin Vft x ACHAChr x hrmin
Where V volume of building in cubic feet
ACH Air changes per hour
Q through infiltration?
Total heat loss Q of this house?
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