Question: f(n) = n^(1/log n), and g(n) = log (n). (Since the math display is a little weird: f(n) is n raised to the power 1/log

f(n) = n^(1/log n), and g(n) = log (n). (Since the

f(n) = n^(1/log n), and g(n) = log (n). (Since the math display is a little weird: f(n) is n raised to the power 1/log (n).) f(n) = o(g(n)) f(n) =O(g(n)) f(n) = Theta (g(n)) f(n)= Ohm (g(n)) f(n) = omega (g(n))

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