For #$1-9,$ find each limit$,$ if it exists:

$\underset{x-5}{lim}\frac{x^2-25}{x+5}$

$\underset{x-3}{lim}\frac{6}{x+3}$

$\underset{h0}{lim}\frac{(3(x+h)-2)-(3x-2)}{h}$

$\underset{x1}{lim}(3x^3-4x^2+2x+3)$

$,\underset{h0}{lim}(x+h{)}^2$

$\underset{h0}{lim}\frac{((x+h{)}^2+1)-(x^2+1)}{h}$

$\underset{x-2}{lim}\frac{x^2+5x+6}{x+2}$

$\underset{x0}{lim}\frac{6-x}{4x}$

$\underset{x2}{lim}\frac{x^2+3x-10}{3x-6}$