Question: For 1 y l n ( y ) - l n ( x ) y - x 1 x f ( t ) = l

For 1yln(y)-ln(x)y-x1xf(t)=ln(t)?,0-?,0y-=f(t)=ln(t)1x1c01y1y1yln(y)-ln(x)y-x1x0, then 1xD1c?01y1y.So1yln(y)-ln(x)y-x1x.
Need Help? x.
For f(t)=ln(t), this is?0-?0
Because 0, then 1xD1c?01y1y.So1yln(y)-ln(x)y-x1x.
Need Help? [x,y],0.
By the Mean Value Theorem, ?,0-?,0y-= for x.
For f(t)=ln(t), this is?0-?0
Because 0, then 1xD1c?01y1y.So1yln(y)-ln(x)y-x1x.
Need Help? 0, use the Mean Value Theorem to show that
1yln(y)-ln(x)y-x1x
Let f(t)=ln(t)on[x,y],0.
By the Mean Value Theorem, ?,0-?,0y-= for x.
For f(t)=ln(t), this is?0-?0
Because 0, then 1xD1c?01y1y.So1yln(y)-ln(x)y-x1x.
Need Help?
For 1 y < l n ( y ) - l n ( x ) y - x < 1 x f ( t

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