For ( (7, -4) ): [ \begin{align} 2a + 3b &= 7 \ a + 2b &= -4 \end{align} ] From the second equation, solve for ( a ): [ a = -4 - 2b ] Substitute ( a ) in the first equation: [ 2(-4 - 2b) + 3b = 7 \ -8 - 4b + 3b = 7 \ -b = 15 \ b = -15 ] Now, substitute ( b ) back to find ( a ): [ a = -4 - 2(-15) \ a = -4 + 30 \ a = 26 ] So, the coordinates of ( (7, -4) ) in the basis ({(2, 1), (3, 2)}) are ( (26, -15) ). For ( (11, -7) ): [ \begin{align} 2c + 3d &= 11 \ c + 2d &= -7 \end{align} ] From the second equation, solve for ( c ): [ c = -7 - 2d ] Substitute ( c ) in the first equation: [ 2(-7 - 2d) + 3d = 11 \ -14 - 4d + 3d = 11 \ -d = 25 \ d = -25 ] Now, substitute ( d ) back to find ( c ): [ c = -7 - 2(-25) \ c = -7 + 50 \ c = 43 ] So, the coordinates of ( (11, -7) ) in the basis ({(2, 1), (3, 2)}) are ( (43, -25) ). Matrix of ( T ) in the nonstandard basis: [ \begin{bmatrix} 26 & 43 \ -15 & -25 \end{bmatrix} ] This matrix should be entered into the system to complete the answer for question use this formula to solve my question (2,1)(3,2)