Question: For a coaxial cable with the shown cross-section, the inner radius equals L1 = 4 meters, and the outer radiuses L2 = 10 meters

For a coaxial cable with the shown cross-section, the inner radius equals 

L1 = 4 meters, and the outer radiuses L2 = 10 meters and L3= 15 meters. All materials in the coaxial are diamagnetic (ur 

For a coaxial cable with the shown cross-section, the inner radius equals L1 = 4 meters, and the outer radiuses L2 = 10 meters and L3= 15 meters. All materials in the coaxial are diamagnetic (ur = 1). The inner conductor carries the current I1 = 9 Ain +az direction, and the return current flows through the outer conductor. Find: 1. The magnetic field intensity for {p = [2.2]} = H1a* 2. The total magnetic flux passes through the area 0 < p < L1 and 0 < < < 1 3. The inductance per unit length for the inner conductor 0 < p < L1 4. The magnetic field intensity for {p = [6.5]} = H2a 5. The total magnetic flux passes through the area L1 < p 6. The inductance per unit length for the dielectric range L1 < p < L2 7. The magnetic field intensity for {p [12.5]} = H3a* 8. The total magnetic flux passes through the area L2 < p < L3 and 0 < z < 1 9. The inductance per unit length for the outer conductor L2 < p < L3 l

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