For a given reaction, the rate constant doubles when the temperature is increased from $56\mathrm{.}8C$ to $84\mathrm{.}8C.$ What is the activation energy for this reaction? $)=(8\mathrm{.}314\frac{J}{K}$mol

$2\mathrm{.}43$E$-2$ kJ$/$mol

$24\mathrm{.}3k\frac{J}{m}ol$

$243k\frac{J}{m}ol$

$-24\mathrm{.}3k\frac{J}{m}ol$

$-2\mathrm{.}43k\frac{J}{m}ol$