For all sets A and B$,$ Ac Bc $($A B$)$c$.$The following is a proposed proof for the statement.Suppose A and B are any sets, such that x Ac Bc$.$Then x Ac or x Bc by definition of union.It follows that x A or x B by definition of complement, and so x A B by definition of union.Thus x $($A B$)$c by definition of complement, and hence Ac Bc $($A B$)$c by definition of subset.Identify the error$($s$)$ in the proposed proof. $($Select all that apply.$)$It is possible for x Ac Bc to be true and x Ac or x Bc to be false.The proof assumes what is to be proved.It is possible for x A or x B to be true and x A B to be false.The proof does not handle the case when A B$.$The proof does not handle the case when B A$.$