For alphabet $\{0,1\},$ the behavior of a Turing machine M can be described as follows:

$1.$ Scan the tape and mark the first O that has not been marked. If no unmarked $0$ is found, go

to stage $4.$ Otherwise, move the head back to the front of the tape.

$2.$ Scan the tape and mark the first $1$ that has not been marked. If no unmarked $1$ is found,

reject.

$3.$ Move the head back to the front of the tape and go to stage $1.$

$4.$ Move the head back to the front of the tape. Scan the tape to see if any unmarked $1$s

remain. If none are found, accept; otherwise, reject.

The correct statements are:

$$ LM$)=\{$w $|$ w contains an equal number of Os and $15\}$

$$ LM$)=\{$w $|$ w contains more Os than $15\}$

$$ LM$)=\{$w $|$ w contains less Os than $15\}$