Question: For alphabet , given languages L 1 and L 2 over , the set - wise concatenation is defined as L 1 L 2 =

For alphabet , given languages L1 and L2 over , the set-wise concatenation is defined as L1
L2={win**|w=uv for some strings uinL1 and {:vinL2}
Q1.1
1 Point
Consider the alphabet {a,b}. How many strings are in the set {,a,b}@{,a,b}?
0(i.e.l the set is empty)
3
6
9
Some other (finite) number
Infinitely many unique strings
Q1.2
2 Points
Let N1=(Q1,,1,q1,F1) and N2=(Q2,,2,q2,F2) be NFAs. When applying the
construction in Theorem 1.47 to build the NFA N=(Q,,,q1,F2) that recognizes L(N1)@
L(N2), select all and only the statements below that are universally true.
?bar(|Q|)=|Q1|+|Q2|?b
ar(|Q|)=|Q1|*|Q2|
Q1.3
1 Point
The NFA whose state diagram below
is the result of applying the set-wise concatenation construction to obtain a machine that
recognizes the language {win{0,1}**|w has zeros followed by {:1(s)}
True
False, it is the result of applying the union construction instead to obtain the machine that
recognizes the language {win{0,1}**|w has all zeros or all {:1(s)}
() False, it is the result of applying the intersection construction instead to obtain the machine that
recognizes the language {win{0,1}**|w has all zeros and all {:1(s)}
False, it is the result of applying the Kleene star construction instead to obtain the machine that
recognizes the language {0,1}**
For alphabet , given languages L 1 and L 2 over ,

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