Question: For an RSA algorithm with a modulus M = 1 3 x 7 = 9 1 . The public key KP is given by: (

For an RSA algorithm with a modulus M=13x7=91. The public
key KP is given by:
(a)(3,91)(b)(8,91)(c)(9,91)(d)(5,91)
(a)(b)(c)(d)
The private key Ks is given by:
(a)(13,91)(b)(31,91)(c)(29,91)(d) neither a not b nor c
(a)(b)(c)(d)
[EEE8119]
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For the character 32 the cypher text is given by:
(a)3(b)50(c)2(d) neither a not b nor c
(a)(b)(c)(d)
For the character 64 the cypher text is given by:
(a)64(b)63(c)62(d) neither a not b nor c
(a)(b)(c)(d)
For the cypher text 127 the plain text is given by:
(a)40(b)43(c)41(d) neither a not b nor c

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