Question: For any PRG G : { 0 , 1 } lambda - > { 0 , 1 } lambda + l there will

For any PRG G : {0,1}\lambda ->{0,1}\lambda +l there will be many strings in {0,1}\lambda +l that are impossible to get as output of G. Let S be any such set of impossible G-outputs, and consider the following adversary that has S hard-coded:
What is the advantage of A in distinguishing LG from LG ? Why does an ad-
versary like this one not automatically break every PRG?

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