1. For extra practice, return to the scenario about brown M&Ms described in Part 1 of this activity. Take the sample proportion you computed in your response to Question 1, based on a sample of size n = 150, and use that sample proportion to construct a 95% confidence interval. In the space below, show all of your work as you construct the interval. You should also write a confidence statement, similar to what you wrote in response to Question 12, after you have obtained your interval.
   

0.419 + 1.96 0-419 -61- 0.417) = 10.419- 0.25488, 0.419+ 2.0548 8) 1315 = > 60. 36412, 0.47388) Lower bound: 0.364 Upper bound: 0.474 12. Based on your work above, in Question 11, complete the following statement: I am 95% confident... that the true population proportion of students with instagram account is between 0.364 and 0.474 13. Look carefully at your work for Question 11. Without doing any additional work, explain how the confidence interval would have been different had you chosen to construct a 99% confidence interval rather than a 95% confidence interval. width of 992% confidence lenay interval will be wider than that of 95%% confidence interval Since critical value for 29% confidence level is larger than that of 95 confidence level 5 1. You have obtained a random sample of size n = 150 plain M&Ms from the population, and you find that 29 of these M&Ms are brown. What is your sample proportion? Please calculate this value below and round it to three decimal places. S= 29 150 = 0.193 2. Look carefully at the sample proportion you calculated in response to Question 1. Why would it be a bad idea to conclude that the population proportion of brown M&Ms must be exactly equal to the value of the sample proportion that you computed? Sample is the representative of population. A parameter is a humber describing a whole population, while a statistic is a humber describing a sample. Sample statistics is not be exactly equal to population parameter It will