Question: for good rating please type (explain also ) Coulomb's law for the magnitude of the force F between two particles with charges Q and Q'

for good rating please type (explain also )

for good rating please type (explain also ) Coulomb's law for themagnitude of the force F between two particles with charges Q andQ' separated by a distance d is F - K 190'1 d2

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is F - K 190'1 d2 where K = 1 , and 60 - 8.854 x 10-12 C2 / (N . m?) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -20.0 nC , is located at X] = -1.725 m ; the second charge, 92 = 35.5 nC, is at the origin (z = 0).What is ( Fnet 3 )z. the x-component of the net force exerted by these two charges on a third charge 93 = 47.0 nC placed between qi and q2 at 23 = -1.060 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. View Available Hint(s) AED ? (Fnet 3)2 = - 3.5 . 10 5 N Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining

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