For $h(x)=\frac{2x}{sin(x)},$ find $h^{\text{'}}(x)$

A$).{\text{'}}^{\text{'}}(x)=\frac{2sin(x)-2xcos(x)}{si{n}^2(x)}$

${?}^B$

c$)h^{\text{'}}(x)=\frac{2sin(x)-2xcos(x)}{co{s}^2(x)}$

D$)h^{\text{'}}(x)=\frac{2sin(x)-2xsin(x)}{si{n}^2(x)}$