Question: For lead 2 0 6 8 2 Pb ( atomic mass = 2 0 5 . 9 7 4 4 4 0 u ) obtain

For lead 20682 Pb (atomic mass =205.974440 u) obtain (a) the mass
defect in atomic mass units, (b) the binding energy (in MeV), and (c) the binding energy per nucleon (in MeV).

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