For nN, use Cauchy's Formula to evaluate Hence show that and e(2) dz. =1 eos(nv) 0...

  

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For nN, use Cauchy's Formula to evaluate Hence show that and e(2") dz. =1 eos(nv) 0 cos (sin(n)) d = 2 0 ecos(n) sin (sin(n)) dv = 0. For nN, use Cauchy's Formula to evaluate Hence show that and e(2") dz. =1 eos(nv) 0 cos (sin(n)) d = 2 0 ecos(n) sin (sin(n)) dv = 0.

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To evaluate the integral z1 eznz dz using Cauchys formula we can write the integrand as a Laurent se... View the full answer