For Nos. $27-32$ : A beam is loaded, as shown in the figure, Let $x$ be the distance measured from the left end of the beam.

The moment equation in segment $CD$ is

$kN-m.$

$($a$)30\mathrm{.}625x-15(x)(\frac{x}{2})+5$

$($b$)30\mathrm{.}625x-80(x-2)+5$

$($c$)39\mathrm{.}375x-15(x)(x-2)+5$

$($d$)39\mathrm{.}375x-90(x-2)+5$

The value of the shear force at $6$ m from the left support is

kd$.$

$($a$)-60$

$($b$)-20\mathrm{.}625$

The magnitude of the maximum shear force is

$($c$)-15\mathrm{.}825$

$($d$)10$

$($a$)30\mathrm{.}625$

$($b$)39\mathrm{.}375$

kN $,$

The magnitude of the maximum negative moment is

$($a$)40$

$($b$)60$

$kN-m.$

$($c$)60$

$($d$)20\mathrm{.}825$

The magnitudo of the maximum positive moment is

$kN-m.$

$($c$)51\mathrm{.}68$

$($d$)31\mathrm{.}24$

$($a$)40$

$($b$)60$

The location of the maximum positive moment is at

$($c$)51\mathrm{.}68$

$($d$)31\mathrm{.}24$

$($a$)$ point D

$($b$)$ point B

$($c$)2\mathrm{.}625$ m from point $A$

$($d$)2\mathrm{.}04$ mft