For problems $6,$ through $11,$ use the following beginning values of the P$1$OUT register:

P$1$OUT

bit

$7$

bit

$6$

bit

$5$

bit

$4$

bit

$3$

bit

$2$

bit

$1$

bit

$0$

$01001100$

$6.$ Write a line of code to set bit$3$ and bit $4$ of the P$1$OUT register while leaving the other bits

unchanged, and then show the result

P$1$OUT

bit

$7$

bit

$6$

bit

$5$

bit

$4$

bit

$3$

bit

$2$

bit

$1$

bit

$0$

NAME: $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

$7.$ Write a line of code to reset or clear bit$3$ and bit $4$ of the P$1$OUT register while leaving the

other bits unchanged, and then show the result, and show the result

P$1$OUT

bit

$7$

bit

$6$

bit

$5$

bit

$4$

bit

$3$

bit

$2$

bit

$1$

bit

$0$

$8.$ Write a line of code to toggle bit$3$ and bit $4$ of the P$1$OUT register while leaving the other

bits unchanged, and then show the result, and show the result

P$1$OUT

bit

$7$

bit

$6$

bit

$5$

bit

$4$

bit

$3$

bit

$2$

bit

$1$

bit

$0$

The following constants are defined in the $$include file$$ msp$430$g$2553.$h to make $$bit

twiddling$$ more intuitive:

#define BIT$0(0$x$0001)$

#define BIT$1(0$x$0002)$

#define BIT$2(0$x$0004)$

#define BIT$3(0$x$0008)$

#define BIT$4(0$x$0010)$

#define BIT$5(0$x$0020)$

#define BIT$6(0$x$0040)$

#define BIT$7(0$x$0080)$

#define BIT$8(0$x$0100)$

#define BIT$9(0$x$0200)$

#define BITA $(0$x$0400)$

#define BITB $(0$x$0800)$

#define BITC $(0$x$1000)$

#define BITD $(0$x$2000)$

#define BITE $(0$x$4000)$

#define BITF $(0$x$8000)$

NAME: $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

$9.$ Show the result of the following line of code:

P$1$OUT &$=$ ~BIT$6$ & ~BIT$7$;

P$1$OUT

bit

$7$

bit

$6$

bit

$5$

bit

$4$

bit

$3$

bit

$2$

bit

$1$

bit

$0$

$10.$ Show the result of the following line of code:

P$1$OUT $|=$ BIT$6|$ BIT$7$;

P$1$OUT

bit

$7$

bit

$6$

bit

$5$

bit

$4$

bit

$3$

bit

$2$

bit

$1$

bit

$0$

$11.$ Show the result of the following line of code:

P$1$OUT $^=$ BIT$6|$ BIT$7$;

P$1$OUT

bit

$7$

bit

$6$

bit

$5$

bit

$4$

bit

$3$

bit

$2$

bit

$1$

bit