Question: For t>0, log(t over t + 1) = a. log(t) - log(t+1) b. log(t) over log(t+1) c. log(t+1) d. log(1/2) If logk(x) = -3 then

For t>0, log(t over t + 1) =

a. log(t) - log(t+1)

b. log(t) over log(t+1)

c. log(t+1)

d. log(1/2)

If logk(x) = -3 then x =

a. -1/k^3

b. -3k

c. 1 over k^3

d. 1 over 3k

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