For the beam shown below the distributed load values shown are $w_1=6k\frac{N}{m}$ and $w_2=4k\frac{N}{m}$ and the length $/=5m.$ Knowing that the vertical reaction at support $A$ is $A_y=5kN,$ determine the reaction at support $B.$

$B_y=45,$

$kN$

no nnecihle enrrect answer is: $45$

$V_1=,5$

$kN$

One possible correct answer is: $5$

$V_2=$

$kN$

One possible correct answer is: $-25$

$V_3=$

$kN$

$x_{\text{z}\text{e}\text{r}\text{o}\text{s}\text{h}\text{e}\text{a}\text{r}}=$

$4\mathrm{.}472$

$x$

$m$

One possible correct answer is: $4\mathrm{.}0824829046386$

$M_1=$

$$One possible correct answer is: $13\mathrm{.}608276348795$

$M_2=$

$kN*m$