Question: For the equation given below, evaluate y' at the point (2, -1).2xy - 3x = -28.y' at (2, -1) = 7/6

For the equation given below, evaluate y' at the point (2,
-1).2x³y - 3x² = -28.y' at (2, -1) = 7/6

For the equation given below, evaluate y' at the point (2, -1).2x³y - 3x² = -28.y' at (2, -1) = 7/6

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