Question: For the following Grammar: S -> LD; | D; D -> i:Y Y -> t Y -> r Y -> c Y -> an.noY Y
For the following Grammar:
S -> LD; | D;
D -> i:Y
Y -> t
Y -> r
Y -> c
Y -> an.noY
Y -> eLd
This grammar is not LL(1). Please show which rules cause the grammar to not be LL(1), and explain why. Then convert the grammar to LL(1) and explain how all the rules are placed in the parse table.
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