Question: For the following system, nd a correct expression for the scalar function x405). The initial conditions are x1(0) = O, x2(0) = O, x3(0) =

For the following system, nd a correct expression for the scalar

For the following system, nd a correct expression for the scalar function x405). The initial conditions are x1(0) = O, x2(0) = O, x3(0) = 1, and x4(0) = 5. (The structure of coefcient matrix makes calculation of eigenvalues easy.) X1 =X1. x2' = 2x1 + 2x2. X3' = 3x2 + 3X3. X4J = 4X3 + 4X4. {:4 (t) = 63'\" 3* {1:4 (t) = 38' + 23* 334 (t) = 8% + 4:63:51\"3 334 (t) = 483: + 842

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