Question: For the function f ( x ) = 2 . 2 5 x ^ 3 3 x ^ 2 + 2 1 . 5 e

For the function f ( x )=2.25x^33x^2+21.5e^x
a. Find the root of f on the interval [2,3] with a tolerance of 1012 using Newtons
method with an initial guess of 2. Use the approximate absolute error as your stopping
condition. Print the root and the number of iterations required.

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