Question: For the function f ( x , y ) = 5 - x 2 - y 2 - 4 , find a unit tangent vector

For the function f(x,y)=5-x2-y2-4, find a unit tangent vector to the level curve at the point (-4,-2) that has a positive x component.
For the function f ( x , y ) = 5 - x 2 - y 2 - 4

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