Question: For the function f(x)=18x212x+12, there exists a root in the interval Selected Answer: Answers: x1=1,xu=+1xu=1,xu=+1 x=10,xu=+10noneofthesex=+5,xu=+6x=5,xu=3

For the function f(x)=18x212x+12, there exists a root in the interval Selected Answer: Answers: x1=1,xu=+1xu=1,xu=+1 x=10,xu=+10noneofthesex=+5,xu=+6x=5,xu=3

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