Question: For the IEEE 32-bit floating point representation except with a 6 bit exponent (bias of 31) and a denorm implicit exponent of 30(The extra bits

For the IEEE 32-bit floating point representation except with a 6 bit exponent (bias of 31) and a denorm implicit exponent of 30(The extra bits will go toward the significand, meaning it is now 25 bits long), how many NaNs can be represented with this floating point system? Convert the floating point number 0x53530000, which follows the 6 bit exponent representation as described above, to decimal.

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