For the infinite square well with $V=0$ inside and infinite outside.

$(x)=\frac{1}{}{\displaystyle \underset{0}{\overset{x}{}}}p(x^{\text{'}})d{x}^{\text{'}}{\displaystyle \underset{0}{\overset{a}{}}}p(x)dxn[n+(\frac{1}{2})]n$