For the probability distribution, find

a$.x$

b$.P(y>2)$

c$.)=(6$

d$.P(y=6)$

$f(y)=\{\begin{array}{cc}0\mathrm{.}05,& y=-2\\ 0\mathrm{.}10,& y=-1\\ 0\mathrm{.}15,& y=0\\ 0\mathrm{.}20,& y=1\\ x_i,& y=2\end{array}$

e$.)=(4$

f$.)=(6$

g$.)=(5\mathrm{.}5$

h$.F(4)$

f$.$ Mean of X