For the pseudo-code program below and its auxiliary functions: print f.9. -6, -8, 8) define abs(X) if (x 0) n 1/2 count - count + 1 return count define f2ccount - 1 while (count > 0) n-n2 count ount - 1 return The output of the program will be: 065.8.256 O 65,7,128 0 65, 6, 128 65,7,65 65, 6, 04