For the reaction 2 NO2(g) N2O4 (g), Hrxn = -58.0 kJ/mol and S = -176.6 J/Kmol.
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Question:
For the reaction 2 NO2(g) ↔ N2O4 (g), ΔH°rxn = -58.0 kJ/mol and ΔS° = -176.6 J/K·mol. Calculate ΔG° and the equilibrium constant K.
Related Book For
Chemistry The Central Science
ISBN: 978-0321696724
12th edition
Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward
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