for this given information below solve question $1$ and $2$ and give the procedure of solving?

Fatal accident rate $($FAR$)$

The FAR is used mostly by the British chemical industry. The FAR reports the number of fatalities based on $1000$

employees working their entire lifetime. The employees are assumed to work a total of $50$ years. Thus the FAR is

based on $108$ working hours. The resulting equation is

FAR $=\frac{\text{N}\text{u}\text{m}\text{b}\text{e}\text{r}of\text{f}\text{a}\text{t}\text{a}\text{l}\text{i}\text{t}\text{i}\text{e}\text{s}{10}^8}{\text{T}\text{o}\text{t}\text{a}\text{l}\text{h}\text{o}\text{u}\text{r}\text{s}\text{w}\text{o}\text{r}\text{k}\text{e}\text{d}by\text{a}\text{l}\text{l}\text{e}\text{m}\text{p}\text{l}\text{o}\text{y}\text{e}\text{e}\text{s}\text{d}\text{u}\text{r}\text{i}\text{n}\text{g}\text{p}\text{e}\text{r}\text{i}\text{o}\text{d}\text{c}\text{o}\text{v}\text{e}\text{r}\text{e}\text{d}}$

Fatality rate, or deaths per person per year

This system reports only the number of fatalities expected per person per year. This approach is useful for

performing calculations on the general population, where the number of exposed hours is poorly defined. The

applicable equation is

Fatality rate $or$ deaths per person per year $=\frac{\text{N}\text{u}\text{m}\text{b}\text{e}\text{r}of\text{f}\text{a}\text{t}\text{a}\text{l}\text{i}\text{t}\text{i}\text{e}\text{s}\text{p}\text{e}\text{r}\text{y}\text{e}\text{a}\text{r}}{\text{T}\text{o}\text{t}\text{a}\text{l}\text{n}\text{u}\text{m}\text{b}\text{e}\text{r}of\text{p}\text{e}\text{o}\text{p}\text{l}\text{e}in\text{a}\text{p}\text{p}\text{l}\text{i}\text{c}\text{a}\text{b}\text{l}\text{e}\text{p}\text{o}\text{p}\text{u}\text{l}\text{a}\text{t}\text{i}\text{o}\text{n}}$

An employee works in a plant with a FAR of $4.$ If this employee works a $4-$hr shift, $200$ days per

year, what are the expected deaths per person per year?

$($Ans: $3\mathrm{.}2*{10}^{-5})$

Three process units are in a plant. The units have FARs of $0\mathrm{.}5,0\mathrm{.}3,$ and $1\mathrm{.}0,$ respectively.

a$)$ What is the overall FAR for the plant, assuming worker exposure to all three units

simultaneously?

b$)$ Assume now that the units are far enough apart that an accident in one would not affect the

workers in another. If a worker spends $20\%$ of his time in process area $1,40\%$ in process area

$2,$ and $40\%$ in process area $3,$ what is his overall FAR?

$($Ans: a$.1\mathrm{.}8$ deaths$/$year$,$ FAR $=0\mathrm{.}62$ deaths $\frac{?}{{10}^{8}hrs})$