For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. In a marketing survey, a random sample of 986 supermarket shoppers revealed that 268 always stock up on an item when they find that item at a real bargain price.

(a)Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.)

__________ (b)Find a 95% confidence interval for p. (For each answer, enter a number. Round your answers to three decimal places.) lower limit__________ upper limit__________ Give a brief explanation of the meaning of the interval.

We are 95% confident that the true proportion of shoppers who stock up on bargains falls within this interval.

We are 5% confident that the true proportion of shoppers who stock up on bargains falls within this interval.

We are 95% confident that the true proportion of shoppers who stock up on bargains f al ls outside this interval.

We are 5% confident that the true proportion of shoppers who stock up on bargains falls above this interval.

(c)As a news writer, how would you report the survey results on the percentage of supermarket shoppers who stock up on items when they find the item is a real bargain?Report the confidence interval.

Report p along with the margin of error.

Report the margin of error.

Report p.

What is the margin of error based on a 95% confidence interval? (Enter a number. Round your answer to three decimal places.)

_____________