Question: For this problem, ignore gravitational interactions, and use k = 9.00 x 109 N m/c. Note that 1 nanocoulomb (1 nC) is equal to

For this problem, ignore gravitational interactions, and use k = 9.00 x 109 N m/c. Note that 1 nanocoulomb (1 nC) is equal to 1 x 10-9 C. A particle with an unknown charge is fixed in position at a location on the x axis. You then bring in a second particle, with a known charge Q2, and measure the force the second particle experiences when it is placed at two different locations on the x-axis. The force the second particle experiences is applied by the particle with the unknown charge, which we refer to as the mystery charge or mystery particle, below. Part (a) Homework Answered Due Jan 30th, 12:15 PM Use these numbers: Q = +500 nC. When the second particle is placed on the x-axis at x = +22.0 cm, it experiences a force of 1.20 N in the positive x-direction. When the second particle is moved to x = +30.0 cm on the x-axis, it experiences a force of 3.20 N in the negative x-direction. Determine the location of the mystery charge. x= cm Type your numeric answer and submit 26.3 Answered - Incorrect 4 attempts left Part (b) Homework Unanswered Due Jan 30th, 12:15 PM Determine the sign and magnitude of the charge on the mystery particle. Express your answer in nanocoulombs. nC Type your numeric answer and submit Unanswered 5 attempts left You are incorrect Resubmit Open in Re Submit

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