For this question, we will find the FS coefficients via FT. We are given the single-lobe, aperiodic halfwave cosine as in Fig. 2, or g(t) = cos(2nt) for t 0.25. Note that this signal is not periodic and it is zero for t> 0.25 second. 1 0.8 0.0 IN idzsoa 0.4 0.2 0 -0.6 Aperiodic Single-Lobe Half Cosine, cos(2 t) -0.4 000 -0.2 0 Time [sec] 0.2 0.4 0.6 Figure 2: Aperiodic Half-cosine, cos(2t) for Q.2 (a) (10 Pts.) Determine the FT the signal in Fig. 2, g(t). (b) (5 Pts.) Now assume that this signal is periodic with T = 1 second. Determine the FS coefficients from the FT determined in Part (a) of this question.