For this study, has the expected frequencies assumption been met? How do you know?

Will we reject or not reject our null hypothesis that the variables are independent? How do you know?

Where would YOU 100K next 111 the output\"! Chapter 18 Chi-square Test of Independence Certain editors at Sage like to think they're a bit of a whiz at soccer. To see how well they play compared with Sussex lecturers and postgraduates, we invited various employees of Sage to join in our soccer matches. Every player was allowed only to play in one match. Over many matches, we counted the number of players that scored goals. A chi-square test of independence was conducted. From the output below, determine whethergrnotthe variables are independent of each other. Use the following tables for questions 7 through 10. Job * Did they score a goal? Crosstahulation Count Expected Count "It: within Job "It: within Did they score a goal? \"A: of Total University of Sussex Count Expected Count "It: within Job "It: within Did they score a goal? \"A: of Total Count Expected Count "It: within Job "It: within Did they score a goal? \"A: of Total Page 20 of 20 Chi-Square Tests Value df Asymp Sig. (2- Exact Sig. (2- Exact Sig. (1- Point sided) sided) sided) Probability Pearson Chi-Square 9.587a 003 002 000 Continuity Correctionb 2.725 .099 Likelihood Ratio 3.834 050 075 047 Fisher's Exact Test .075 047 Linear-by-Linear 3.5870 1 058 .075 047 .034 Association N of Valid Cases 77 a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 8.73. b. Computed only for a 2x2 table c. The standardized statistic is -1.894