Question: For what value of k will the function y = 3x+4r-7/x-5x+k have asymptotes at x = 6, x= -1, and y = 3?(A) k=6(B) k=-6(C)

For what value of k will the function y = 3x²+4r-7/x²-5x+k have asymptotes at x = 6, x= -1, and y = 3?(A) k=6(B) k=-6(C) No such value of k exists because regardless of the horizontal asymptote is y = 0(D) No such value of k exists because there will be a hole, not a vertical asymptote, at x= -1

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