For $y=f(x)=2x^3,x=5,$ and $x=0\mathrm{.}02$ find

$ay$ for the given $x$ and $x$ values,

$bdy=f^{\text{'}}(x)dx,$

$cdy$ for the given $x$ and $x$ values.

$ay=$

$(Roundto$ four decimal places $as$ needed.$)$