fork not printing pid, current$\_$pid and parent$\_$pid please help #include

#include

#include

#include

int main$()$

$\{$

pid$\_$t pid;

char $*$message;

int n;

printf$("$fork program starting

$")$;

pid $=$ fork$()$;

switch $($pid$)$

$\{$

case $-1$:

perror$("$fork failed"$)$;

exit$(1)$;

case $0$:

message $=$ "This is the child";

n $=5$;

break;

default:

message $=$ "This is the parent";

n $=3$;

waitpid$($pid$,$ NULL, $0)$;

break;

$\}$

for $($; n $>0$; n$--)$

$\{$

printf$("\%$s; pid$=\%$d; current$\_$pid$=\%$d; parent$\_$pid$=\%$d;

$",$

message, getpid$(),($int$)$getpid$(),($int$)$getppid$())$;

sleep$(1)$;

$\}$

exit$(0)$;

$\}$

ouput should look like this fork program starting

This is the parent; pid$=9774$; current$\_$pid$=9773$; parent$\_$pid$=365$;

This is the child; pid$=0$; current$\_$pid$=9774$; parent$\_$pid$=9773$;

This is the parent; pid$=9774$; current$\_$pid$=9773$; parent$\_$pid$=365$;

This is the child; pid$=0$; current$\_$pid$=9774$; parent$\_$pid$=9773$;

This is the parent; pid$=9774$; current$\_$pid$=9773$; parent$\_$pid$=365$;

This is the child; pid$=0$; current$\_$pid$=9774$; parent$\_$pid$=9773$;

This is the child; pid$=0$; current$\_$pid$=9774$; parent$\_$pid$=9773$;

$ This is the child; pid$=0$; current$\_$pid$=9774$; parent$\_$pid$=1$;

Once your output looks similar to what is shown above change the code to include two more children. This may require additional conditionals. Now, one parent and three children should be executing.