Question: Formulate but do not solve an algebraic model for the following situation. City bus drivers work two four-hour shifts per day. In some cases, the

Formulate but do not solve an algebraic model for the following situation. City bus drivers work two four-hour shifts per day. In some cases, the two shifts are consecutive (effectively one eight-hour shift), but usually they are not. All drivers earn a base rate of $26.25 per hour (i.e. $210 per day). Because of the inconvenience of breaking up the day, those who work non-consecutive shifts are paid a $18 per day bonus. The city bus service has the following daily requirements for drivers:


shifttime of dayminimum number of drivers needed
10500 to 0859150
20900 to 125980
31300 to 165990
41700 to 2059160
52100 to 005970


Nobody will be working on both shifts 1 and 5. Subject to meeting all its requirements for drivers. the city bus service wants to minimize its daily labour cost (regular and bonus)


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As noone will work on 1 and 5 shifts commonly if we manage the drivers in all shifts we get 70 ext... View full answer

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