Question: FQ 0 5 a ) 3 . 0 1 0 0 ) 3 . 0 kJ 2 H 2 + 0 2 - > 2

FQ05 a)3.0100)3.0 kJ 2H2+02->2H20483.6 mol of 02 c)3 MeV 1H + H H +1H +4.03

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