frequency(d) 3 pts Given a dictionary d, where it is guaranteed that keys are strings and values are integers, return the value in d with the highest occurrence. If more than one value occurs the most, return the value that appeared first in d. Tip : Create a new dictionary to keep track of value frequency You are NOT allowed to use count(), max(), min() or any other Python count libraries such as Counter and mode (No credit will be given to your code if you use them) Preconditions d: non-empty dictionary Returns: int -> value that occurs the most times in d

Preconditions

d1: dict

d2: dict

Returns: dict -> key:value pairs that appear in both d1 and d2

Examples:

>>> intersection({'a':5, 'b':7, 'd':5},{'d':5, 'a':5, 'b':9, 'c':12}) {'a': 5, 'd': 5}

>>> intersection({'a':5, 'b':7, 'd':5},{'d':8, 'a':51, 'b':9, 'c':12}) {}

>>> intersection({'a':5, 'b':7, 'd':5, 'c':'32', 't':35.6},{'d':8, 'a':1, 'b':9, 'c':'32'}) {'c': '32'}

def frequency(d): """ >>> frequency({'a':2, 'b': 2, 'c':1, 'd':1, 'e': 5, 'f': 1}) 1 >>> frequency({'a':2, 'b': 2, 'c':1, 'd':1}) 2 >>> frequency({'a':2, 'b': 2, 'c':1, 'd':1, 'h': 2, 't': 6, 'rr': 6, 'rws':6}) 2 >>> frequency({'a':2, 'b': 2, 'c':1, 'd':1, 'h': 2, 't': 6, 'rr': 6, 'rws':6, 'ret': 6, 'z': 5}) 6 """ # - YOUR CODE STARTS HERE -