Question: From a regular deck of 52 playing cards placed face-side down, what are the chances that on two consecutive selections WITHOUT replacing the first card

From a regular deck of 52 playing cards placed face-side down, what are the chances that on two consecutive selections WITHOUT replacing the first card you selected to the deck, you select an ace given that you already selected an ace with your first selection? (Present the formula with the variables and then the equation with the numbers, and then do the math despite how trivial it may seem. In the long run of the logicality of probability calculus, it is not trivial.)

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