From the textbook:

Let h$($x$)=2$x$^(2)+3$x$+1.$

Let g$($x$)=\backslash$root$(2)($x$)+3$nth root of a quantity in Edfinity, you can

use the power $(1)/($n$).$ For example, $\backslash$root$(5)(2$x$+3)=(2$x$+3)^((1)/(5)),$ and so

to express this in Edfinity you can write $(2$x$+3)^((1)/(5))$ g$($h$($x$))=$

$($b$)$ h$($g$($x$))=$

$($c$)$ h$($h$($x$))=$

$2(2$x$^(2)+3$x$+1)^(2)+3(2$x$^(2)+3$x$+1)+1$

$($d$)$ g$($x$)+1=$

$($e$)$ g$($x$+1)=$